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5500531034111 = 43912529683449
BaseRepresentation
bin101000000001011000100…
…1100101100011111111111
3201110211211110120011111202
41100002301030230133333
51210110041421042421
615410524205410115
71105254200232101
oct120026114543777
921424743504452
105500531034111
111830842408823
1274a05886993b
1330b90c2419b9
1415032731d571
1598134c9d10b
hex500b132c7ff

5500531034111 has 4 divisors (see below), whose sum is σ = 5513060718000. Its totient is φ = 5488001350224.

The previous prime is 5500531034059. The next prime is 5500531034147. The reversal of 5500531034111 is 1114301350055.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5500531034111 - 222 = 5500526839807 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5500531034161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6264841286 + ... + 6264842163.

It is an arithmetic number, because the mean of its divisors is an integer number (1378265179500).

Almost surely, 25500531034111 is an apocalyptic number.

5500531034111 is a deficient number, since it is larger than the sum of its proper divisors (12529683889).

5500531034111 is a wasteful number, since it uses less digits than its factorization.

5500531034111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12529683888.

The product of its (nonzero) digits is 4500, while the sum is 29.

Adding to 5500531034111 its reverse (1114301350055), we get a palindrome (6614832384166).

The spelling of 5500531034111 in words is "five trillion, five hundred billion, five hundred thirty-one million, thirty-four thousand, one hundred eleven".

Divisors: 1 439 12529683449 5500531034111