Base | Representation |
---|---|
bin | 111110100010101011001110… |
… | …0101101111101111100000001 |
3 | 2200010211021221122202112211012 |
4 | 1331011112130231331330001 |
5 | 1034101210424420412113 |
6 | 5230003130514530305 |
7 | 223606053356245544 |
oct | 17505263455757401 |
9 | 2603737848675735 |
10 | 550123515404033 |
11 | 14a31708883406a |
12 | 51849758296995 |
13 | 1a7c656a6a1b4c |
14 | 99bc197c1885b |
15 | 438ee95e64aa8 |
hex | 1f4559cb7df01 |
550123515404033 has 32 divisors (see below), whose sum is σ = 573218668339200. Its totient is φ = 527368126279680.
The previous prime is 550123515404027. The next prime is 550123515404039. The reversal of 550123515404033 is 330404515321055.
It is an interprime number because it is at equal distance from previous prime (550123515404027) and next prime (550123515404039).
It is not a de Polignac number, because 550123515404033 - 222 = 550123511209729 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (550123515404039) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 86402308016 + ... + 86402314382.
It is an arithmetic number, because the mean of its divisors is an integer number (17913083385600).
Almost surely, 2550123515404033 is an apocalyptic number.
It is an amenable number.
550123515404033 is a deficient number, since it is larger than the sum of its proper divisors (23095152935167).
550123515404033 is a wasteful number, since it uses less digits than its factorization.
550123515404033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16577.
The product of its (nonzero) digits is 540000, while the sum is 41.
The spelling of 550123515404033 in words is "five hundred fifty trillion, one hundred twenty-three billion, five hundred fifteen million, four hundred four thousand, thirty-three".
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