Base | Representation |
---|---|
bin | 101000000001111001010… |
… | …0110010010001010111111 |
3 | 201110221122221012001220201 |
4 | 1100003302212102022333 |
5 | 1210114313313323210 |
6 | 15411225123024331 |
7 | 1105323322425343 |
oct | 120036246221277 |
9 | 21427587161821 |
10 | 5501628261055 |
11 | 18312557a9653 |
12 | 74a30420b0a7 |
13 | 30ba55661404 |
14 | 1503ccd39623 |
15 | 9819b28753a |
hex | 500f29922bf |
5501628261055 has 4 divisors (see below), whose sum is σ = 6601953913272. Its totient is φ = 4401302608840.
The previous prime is 5501628261049. The next prime is 5501628261061.
5501628261055 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (5501628261049) and next prime (5501628261061).
It is not a de Polignac number, because 5501628261055 - 235 = 5467268522687 is a prime.
It is a super-3 number, since 3×55016282610553 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5501628260996 and 5501628261014.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 550162826101 + ... + 550162826110.
It is an arithmetic number, because the mean of its divisors is an integer number (1650488478318).
Almost surely, 25501628261055 is an apocalyptic number.
5501628261055 is a deficient number, since it is larger than the sum of its proper divisors (1100325652217).
5501628261055 is a wasteful number, since it uses less digits than its factorization.
5501628261055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1100325652216.
The product of its (nonzero) digits is 720000, while the sum is 46.
The spelling of 5501628261055 in words is "five trillion, five hundred one billion, six hundred twenty-eight million, two hundred sixty-one thousand, fifty-five".
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