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55016713203103 = 72775676359289
BaseRepresentation
bin11001000001001100100111…
…01001011010110110011111
321012210112202100010002002101
430200212103221122312133
524202343212034444403
6313002155031505531
714405553304155031
oct1440462351326637
9235715670102071
1055016713203103
11165915033584a3
126206735b282a7
132491091253322
14d82b74935c51
1565619e7a671d
hex320993a5ad9f

55016713203103 has 4 divisors (see below), whose sum is σ = 55092389563120. Its totient is φ = 54941036843088.

The previous prime is 55016713203091. The next prime is 55016713203119. The reversal of 55016713203103 is 30130231761055.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55016713203103 - 25 = 55016713203071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55016713203173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37838178918 + ... + 37838180371.

It is an arithmetic number, because the mean of its divisors is an integer number (13773097390780).

Almost surely, 255016713203103 is an apocalyptic number.

55016713203103 is a deficient number, since it is larger than the sum of its proper divisors (75676360017).

55016713203103 is an equidigital number, since it uses as much as digits as its factorization.

55016713203103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75676360016.

The product of its (nonzero) digits is 56700, while the sum is 37.

Adding to 55016713203103 its reverse (30130231761055), we get a palindrome (85146944964158).

The spelling of 55016713203103 in words is "fifty-five trillion, sixteen billion, seven hundred thirteen million, two hundred three thousand, one hundred three".

Divisors: 1 727 75676359289 55016713203103