Base | Representation |
---|---|
bin | 11001000001011010001110… |
… | …11101111101100011100111 |
3 | 21012211020121220200011221022 |
4 | 30200231013131331203213 |
5 | 24203003200404100303 |
6 | 313005404350241355 |
7 | 14406232431031511 |
oct | 1440550735754347 |
9 | 235736556604838 |
10 | 55024025065703 |
11 | 16594615749051 |
12 | 62080367b625b |
13 | 249198804b645 |
14 | d83269a72bb1 |
15 | 65647b674438 |
hex | 320b4777d8e7 |
55024025065703 has 4 divisors (see below), whose sum is σ = 55024047742560. Its totient is φ = 55024002388848.
The previous prime is 55024025065663. The next prime is 55024025065729. The reversal of 55024025065703 is 30756052042055.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55024025065703 is a prime.
It is a super-2 number, since 2×550240250657032 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55024025095703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7193750 + ... + 12719987.
It is an arithmetic number, because the mean of its divisors is an integer number (13756011935640).
Almost surely, 255024025065703 is an apocalyptic number.
55024025065703 is a deficient number, since it is larger than the sum of its proper divisors (22676857).
55024025065703 is a wasteful number, since it uses less digits than its factorization.
55024025065703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22676856.
The product of its (nonzero) digits is 1260000, while the sum is 44.
The spelling of 55024025065703 in words is "fifty-five trillion, twenty-four billion, twenty-five million, sixty-five thousand, seven hundred three".
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