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55031025343 = 77861575049
BaseRepresentation
bin110011010000000110…
…101100111010111111
312021001012120201221211
4303100012230322333
51400200420302333
641140401505251
73655501666060
oct632006547277
9167035521854
1055031025343
112137a640938
12a7b9942227
1352601721b8
14294098a567
1516713c8ecd
hexcd01acebf

55031025343 has 4 divisors (see below), whose sum is σ = 62892600400. Its totient is φ = 47169450288.

The previous prime is 55031025317. The next prime is 55031025347. The reversal of 55031025343 is 34352013055.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55031025343 - 25 = 55031025311 is a prime.

It is a super-3 number, since 3×550310253433 (a number of 33 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55031025347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3930787518 + ... + 3930787531.

It is an arithmetic number, because the mean of its divisors is an integer number (15723150100).

Almost surely, 255031025343 is an apocalyptic number.

55031025343 is a deficient number, since it is larger than the sum of its proper divisors (7861575057).

55031025343 is an equidigital number, since it uses as much as digits as its factorization.

55031025343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7861575056.

The product of its (nonzero) digits is 27000, while the sum is 31.

Adding to 55031025343 its reverse (34352013055), we get a palindrome (89383038398).

The spelling of 55031025343 in words is "fifty-five billion, thirty-one million, twenty-five thousand, three hundred forty-three".

Divisors: 1 7 7861575049 55031025343