Base | Representation |
---|---|
bin | 11001000001100111111110… |
… | …11110000010100011111101 |
3 | 21012211221200101012102002121 |
4 | 30200303333132002203331 |
5 | 24203113310201424440 |
6 | 313013025052122541 |
7 | 14406613365664426 |
oct | 1440637736024375 |
9 | 235757611172077 |
10 | 55031407061245 |
11 | 1659776369060a |
12 | 6209556a66451 |
13 | 2492593530b44 |
14 | d8376a22864d |
15 | 65675e79734a |
hex | 320cff7828fd |
55031407061245 has 16 divisors (see below), whose sum is σ = 69753237345792. Its totient is φ = 41614147270080.
The previous prime is 55031407061237. The next prime is 55031407061273. The reversal of 55031407061245 is 54216070413055.
It is not a de Polignac number, because 55031407061245 - 23 = 55031407061237 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (43).
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4128380962 + ... + 4128394291.
It is an arithmetic number, because the mean of its divisors is an integer number (4359577334112).
Almost surely, 255031407061245 is an apocalyptic number.
It is an amenable number.
55031407061245 is a deficient number, since it is larger than the sum of its proper divisors (14721830284547).
55031407061245 is a wasteful number, since it uses less digits than its factorization.
55031407061245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8256775332.
The product of its (nonzero) digits is 504000, while the sum is 43.
The spelling of 55031407061245 in words is "fifty-five trillion, thirty-one billion, four hundred seven million, sixty-one thousand, two hundred forty-five".
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