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55033543151 = 519710589483
BaseRepresentation
bin110011010000010000…
…010011100111101111
312021001101022122201222
4303100100103213233
51400202041340101
641140531453555
73655532253446
oct632020234757
9167041278658
1055033543151
1121381000574
12a7ba7572bb
135260844222
142941043d5d
15167172501b
hexcd04139ef

55033543151 has 4 divisors (see below), whose sum is σ = 55044137832. Its totient is φ = 55022948472.

The previous prime is 55033543093. The next prime is 55033543177. The reversal of 55033543151 is 15134533055.

55033543151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55033543151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55033543351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5289545 + ... + 5299938.

It is an arithmetic number, because the mean of its divisors is an integer number (13761034458).

Almost surely, 255033543151 is an apocalyptic number.

55033543151 is a deficient number, since it is larger than the sum of its proper divisors (10594681).

55033543151 is a wasteful number, since it uses less digits than its factorization.

55033543151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10594680.

The product of its (nonzero) digits is 67500, while the sum is 35.

The spelling of 55033543151 in words is "fifty-five billion, thirty-three million, five hundred forty-three thousand, one hundred fifty-one".

Divisors: 1 5197 10589483 55033543151