Base | Representation |
---|---|
bin | 10000000001000111011… |
… | …01110001001001001101 |
3 | 1221121120012001110211020 |
4 | 20000203231301021031 |
5 | 33004111340423341 |
6 | 1100455105544353 |
7 | 54522211302105 |
oct | 10004355611115 |
9 | 1847505043736 |
10 | 550355014221 |
11 | 1a244a06aa31 |
12 | 8a7b49450b9 |
13 | 3cb8a60b08c |
14 | 1c8ccb68205 |
15 | e4b1752566 |
hex | 8023b7124d |
550355014221 has 4 divisors (see below), whose sum is σ = 733806685632. Its totient is φ = 366903342812.
The previous prime is 550355014213. The next prime is 550355014241. The reversal of 550355014221 is 122410553055.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 550355014221 - 23 = 550355014213 is a prime.
It is a super-2 number, since 2×5503550142212 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (550355014211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91725835701 + ... + 91725835706.
It is an arithmetic number, because the mean of its divisors is an integer number (183451671408).
Almost surely, 2550355014221 is an apocalyptic number.
It is an amenable number.
550355014221 is a deficient number, since it is larger than the sum of its proper divisors (183451671411).
550355014221 is a wasteful number, since it uses less digits than its factorization.
550355014221 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 183451671410.
The product of its (nonzero) digits is 30000, while the sum is 33.
Adding to 550355014221 its reverse (122410553055), we get a palindrome (672765567276).
The spelling of 550355014221 in words is "five hundred fifty billion, three hundred fifty-five million, fourteen thousand, two hundred twenty-one".
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