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55040243530331 = 192896854922649
BaseRepresentation
bin11001000001111000011100…
…01010011111101001011011
321012212210111012120112212102
430200330032022133221123
524203234404320432311
6313021045552234015
714410345354512113
oct1440741612375133
9235783435515772
1055040243530331
11165a0488638624
12620b20223b90b
132493371155487
14d83d67a32043
15656aca42043b
hex320f0e29fa5b

55040243530331 has 4 divisors (see below), whose sum is σ = 57937098453000. Its totient is φ = 52143388607664.

The previous prime is 55040243530313. The next prime is 55040243530339. The reversal of 55040243530331 is 13303534204055.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55040243530331 - 210 = 55040243529307 is a prime.

It is a super-2 number, since 2×550402435303312 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55040243530339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1448427461306 + ... + 1448427461343.

It is an arithmetic number, because the mean of its divisors is an integer number (14484274613250).

Almost surely, 255040243530331 is an apocalyptic number.

55040243530331 is a deficient number, since it is larger than the sum of its proper divisors (2896854922669).

55040243530331 is a wasteful number, since it uses less digits than its factorization.

55040243530331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2896854922668.

The product of its (nonzero) digits is 324000, while the sum is 38.

Adding to 55040243530331 its reverse (13303534204055), we get a palindrome (68343777734386).

The spelling of 55040243530331 in words is "fifty-five trillion, forty billion, two hundred forty-three million, five hundred thirty thousand, three hundred thirty-one".

Divisors: 1 19 2896854922649 55040243530331