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55047040309 = 140659391351
BaseRepresentation
bin110011010001000011…
…110010110100110101
312021002022201101100201
4303101003302310311
51400214020242214
641142133040501
73656055056662
oct632103626465
9167068641321
1055047040309
112138868a148
12a803186131
13526358b801
142942b58a69
1516729de274
hexcd10f2d35

55047040309 has 4 divisors (see below), whose sum is σ = 55047572320. Its totient is φ = 55046508300.

The previous prime is 55047040303. The next prime is 55047040327. The reversal of 55047040309 is 90304074055.

55047040309 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 55047040309 - 215 = 55047007541 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55047040303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55017 + ... + 336334.

It is an arithmetic number, because the mean of its divisors is an integer number (13761893080).

Almost surely, 255047040309 is an apocalyptic number.

It is an amenable number.

55047040309 is a deficient number, since it is larger than the sum of its proper divisors (532011).

55047040309 is a wasteful number, since it uses less digits than its factorization.

55047040309 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 532010.

The product of its (nonzero) digits is 75600, while the sum is 37.

The spelling of 55047040309 in words is "fifty-five billion, forty-seven million, forty thousand, three hundred nine".

Divisors: 1 140659 391351 55047040309