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5505002525303 = 17323823677959
BaseRepresentation
bin101000000011011101110…
…1110000101001001110111
3201111021101002110110021122
41100012323232011021313
51210143221121302203
615412544021134155
71105503044254421
oct120067356051167
921437332413248
105505002525303
111832727457296
1274aaa625a35b
1330c172746188
1415062d127811
15982e7609538
hex501bbb85277

5505002525303 has 4 divisors (see below), whose sum is σ = 5828826203280. Its totient is φ = 5181178847328.

The previous prime is 5505002525299. The next prime is 5505002525387. The reversal of 5505002525303 is 3035252005055.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5505002525303 - 22 = 5505002525299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5505002525203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 161911838963 + ... + 161911838996.

It is an arithmetic number, because the mean of its divisors is an integer number (1457206550820).

Almost surely, 25505002525303 is an apocalyptic number.

5505002525303 is a deficient number, since it is larger than the sum of its proper divisors (323823677977).

5505002525303 is a wasteful number, since it uses less digits than its factorization.

5505002525303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 323823677976.

The product of its (nonzero) digits is 112500, while the sum is 35.

The spelling of 5505002525303 in words is "five trillion, five hundred five billion, two million, five hundred twenty-five thousand, three hundred three".

Divisors: 1 17 323823677959 5505002525303