Base | Representation |
---|---|
bin | 101000000011011110010… |
… | …0101011100011000000101 |
3 | 201111021102002202210102120 |
4 | 1100012330211130120011 |
5 | 1210143233330211331 |
6 | 15412545300200153 |
7 | 1105503311521452 |
oct | 120067445343005 |
9 | 21437362683376 |
10 | 5505017038341 |
11 | 183273466a137 |
12 | 74aaab099059 |
13 | 30c175757c82 |
14 | 150631024829 |
15 | 982e8a24796 |
hex | 501bc95c605 |
5505017038341 has 16 divisors (see below), whose sum is σ = 7453639065600. Its totient is φ = 3613461993648.
The previous prime is 5505017038319. The next prime is 5505017038343. The reversal of 5505017038341 is 1438307105055.
5505017038341 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5505017038341 - 211 = 5505017036293 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5505017038293 and 5505017038302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5505017038343) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 32265781 + ... + 32435946.
It is an arithmetic number, because the mean of its divisors is an integer number (465852441600).
Almost surely, 25505017038341 is an apocalyptic number.
It is an amenable number.
5505017038341 is a deficient number, since it is larger than the sum of its proper divisors (1948622027259).
5505017038341 is a wasteful number, since it uses less digits than its factorization.
5505017038341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64702168.
The product of its (nonzero) digits is 252000, while the sum is 42.
The spelling of 5505017038341 in words is "five trillion, five hundred five billion, seventeen million, thirty-eight thousand, three hundred forty-one".
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