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55050610003 = 320917155067
BaseRepresentation
bin110011010001010001…
…011010010101010011
312021002120102202001121
4303101101122111103
51400220424010003
641142341343111
73656130315154
oct632121322523
9167076382047
1055050610003
112138a6a8104
12a804407a97
13526423b55c
14294340792b
151672e96cbd
hexcd145a553

55050610003 has 4 divisors (see below), whose sum is σ = 55067768280. Its totient is φ = 55033451728.

The previous prime is 55050610001. The next prime is 55050610007. The reversal of 55050610003 is 30001605055.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55050610003 - 21 = 55050610001 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 55050610003.

It is not an unprimeable number, because it can be changed into a prime (55050610001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8574325 + ... + 8580742.

It is an arithmetic number, because the mean of its divisors is an integer number (13766942070).

Almost surely, 255050610003 is an apocalyptic number.

55050610003 is a deficient number, since it is larger than the sum of its proper divisors (17158277).

55050610003 is a wasteful number, since it uses less digits than its factorization.

55050610003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17158276.

The product of its (nonzero) digits is 2250, while the sum is 25.

The spelling of 55050610003 in words is "fifty-five billion, fifty million, six hundred ten thousand, three".

Divisors: 1 3209 17155067 55050610003