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5505253000553 = 23239358826111
BaseRepresentation
bin101000000011100101010…
…1001100100010101101001
3201111022000112202220201202
41100013022221210111221
51210144224232004203
615413024525453545
71105512205256105
oct120071251442551
921438015686652
105505253000553
111832845885029
1274ab561112b5
1330c1b25c3c97
141506544c8905
159830e5d4388
hex501caa64569

5505253000553 has 4 divisors (see below), whose sum is σ = 5744611826688. Its totient is φ = 5265894174420.

The previous prime is 5505253000531. The next prime is 5505253000561. The reversal of 5505253000553 is 3550003525055.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5505253000553 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5505253000523) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119679413033 + ... + 119679413078.

It is an arithmetic number, because the mean of its divisors is an integer number (1436152956672).

Almost surely, 25505253000553 is an apocalyptic number.

It is an amenable number.

5505253000553 is a deficient number, since it is larger than the sum of its proper divisors (239358826135).

5505253000553 is a wasteful number, since it uses less digits than its factorization.

5505253000553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 239358826134.

The product of its (nonzero) digits is 281250, while the sum is 38.

The spelling of 5505253000553 in words is "five trillion, five hundred five billion, two hundred fifty-three million, five hundred fifty-three", and thus it is an aban number.

Divisors: 1 23 239358826111 5505253000553