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5505305255503 = 31177590492113
BaseRepresentation
bin101000000011100110111…
…0000111001111001001111
3201111022011012002202001021
41100013031300321321033
51210144331121134003
615413034033455011
71105513411364644
oct120071560717117
921438135082037
105505305255503
111832872325a39
1274ab6b711467
1330c1c038b881
1415065b40bdcb
1598313ea72bd
hex501cdc39e4f

5505305255503 has 4 divisors (see below), whose sum is σ = 5682895747648. Its totient is φ = 5327714763360.

The previous prime is 5505305255491. The next prime is 5505305255537. The reversal of 5505305255503 is 3055525035055.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 5505305255503 - 233 = 5496715320911 is a prime.

It is a super-2 number, since 2×55053052555032 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5505305255503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5505305255543) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88795246026 + ... + 88795246087.

It is an arithmetic number, because the mean of its divisors is an integer number (1420723936912).

Almost surely, 25505305255503 is an apocalyptic number.

5505305255503 is a deficient number, since it is larger than the sum of its proper divisors (177590492145).

5505305255503 is a wasteful number, since it uses less digits than its factorization.

5505305255503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 177590492144.

The product of its (nonzero) digits is 1406250, while the sum is 43.

The spelling of 5505305255503 in words is "five trillion, five hundred five billion, three hundred five million, two hundred fifty-five thousand, five hundred three".

Divisors: 1 31 177590492113 5505305255503