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55053521245 = 511010704249
BaseRepresentation
bin110011010001011100…
…100001000101011101
312021002202220122112101
4303101130201011131
51400222200134440
641142524005101
73656164131562
oct632134410535
9167082818471
1055053521245
1121391306398
12a805390791
135264a1a698
142943964869
15167336e69a
hexcd172115d

55053521245 has 4 divisors (see below), whose sum is σ = 66064225500. Its totient is φ = 44042816992.

The previous prime is 55053521219. The next prime is 55053521279. The reversal of 55053521245 is 54212535055.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 29797319161 + 25256202084 = 172619^2 + 158922^2 .

It is a cyclic number.

It is not a de Polignac number, because 55053521245 - 25 = 55053521213 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5505352120 + ... + 5505352129.

It is an arithmetic number, because the mean of its divisors is an integer number (16516056375).

Almost surely, 255053521245 is an apocalyptic number.

It is an amenable number.

55053521245 is a deficient number, since it is larger than the sum of its proper divisors (11010704255).

55053521245 is a wasteful number, since it uses less digits than its factorization.

55053521245 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11010704254.

The product of its (nonzero) digits is 150000, while the sum is 37.

The spelling of 55053521245 in words is "fifty-five billion, fifty-three million, five hundred twenty-one thousand, two hundred forty-five".

Divisors: 1 5 11010704249 55053521245