Base | Representation |
---|---|
bin | 101000000011101110010… |
… | …0010011010010011010010 |
3 | 201111022210110111021102112 |
4 | 1100013130202122103102 |
5 | 1210200333044124242 |
6 | 15413114410145322 |
7 | 1105522511221262 |
oct | 120073442322322 |
9 | 21438713437375 |
10 | 5505553114322 |
11 | 183298a226a38 |
12 | 74b01a722242 |
13 | 30c22c8317b1 |
14 | 1506822cb7a2 |
15 | 9832ab16c82 |
hex | 501dc89a4d2 |
5505553114322 has 4 divisors (see below), whose sum is σ = 8258329671486. Its totient is φ = 2752776557160.
The previous prime is 5505553114279. The next prime is 5505553114331. The reversal of 5505553114322 is 2234113555055.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 5389366893001 + 116186221321 = 2321501^2 + 340861^2 .
It is a super-2 number, since 2×55055531143222 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5505553114322.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1376388278579 + ... + 1376388278582.
Almost surely, 25505553114322 is an apocalyptic number.
5505553114322 is a deficient number, since it is larger than the sum of its proper divisors (2752776557164).
5505553114322 is a wasteful number, since it uses less digits than its factorization.
5505553114322 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2752776557163.
The product of its (nonzero) digits is 450000, while the sum is 41.
Adding to 5505553114322 its reverse (2234113555055), we get a palindrome (7739666669377).
The spelling of 5505553114322 in words is "five trillion, five hundred five billion, five hundred fifty-three million, one hundred fourteen thousand, three hundred twenty-two".
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