Base | Representation |
---|---|
bin | 110011010010001110… |
… | …110101010100001011 |
3 | 12021010200201202220012 |
4 | 303102032311110023 |
5 | 1400234034230212 |
6 | 41144114422135 |
7 | 3656414215556 |
oct | 632216652413 |
9 | 167120652805 |
10 | 55066711307 |
11 | 213987a5273 |
12 | a80989194b |
13 | 526768825a |
14 | 29455d969d |
15 | 16745c7922 |
hex | cd23b550b |
55066711307 has 8 divisors (see below), whose sum is σ = 55124908800. Its totient is φ = 55008543744.
The previous prime is 55066711267. The next prime is 55066711331. The reversal of 55066711307 is 70311766055.
55066711307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 55066711307 - 26 = 55066711243 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55066711507) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5855333 + ... + 5864729.
It is an arithmetic number, because the mean of its divisors is an integer number (6890613600).
Almost surely, 255066711307 is an apocalyptic number.
55066711307 is a deficient number, since it is larger than the sum of its proper divisors (58197493).
55066711307 is a wasteful number, since it uses less digits than its factorization.
55066711307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14965.
The product of its (nonzero) digits is 132300, while the sum is 41.
The spelling of 55066711307 in words is "fifty-five billion, sixty-six million, seven hundred eleven thousand, three hundred seven".
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