Base | Representation |
---|---|
bin | 110011010010001110… |
… | …110101010011001011 |
3 | 12021010200201202210211 |
4 | 303102032311103023 |
5 | 1400234034224433 |
6 | 41144114421551 |
7 | 3656414215435 |
oct | 632216652313 |
9 | 167120652724 |
10 | 55066711243 |
11 | 213987a5215 |
12 | a8098918b7 |
13 | 526768820b |
14 | 29455d9655 |
15 | 16745c78cd |
hex | cd23b54cb |
55066711243 has 2 divisors, whose sum is σ = 55066711244. Its totient is φ = 55066711242.
The previous prime is 55066711201. The next prime is 55066711261. The reversal of 55066711243 is 34211766055.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55066711243 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55066711196 and 55066711205.
It is not a weakly prime, because it can be changed into another prime (55066712243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27533355621 + 27533355622.
It is an arithmetic number, because the mean of its divisors is an integer number (27533355622).
Almost surely, 255066711243 is an apocalyptic number.
55066711243 is a deficient number, since it is larger than the sum of its proper divisors (1).
55066711243 is an equidigital number, since it uses as much as digits as its factorization.
55066711243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 151200, while the sum is 40.
The spelling of 55066711243 in words is "fifty-five billion, sixty-six million, seven hundred eleven thousand, two hundred forty-three".
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