Base | Representation |
---|---|
bin | 11001000010110110110101… |
… | …11100110111111010100111 |
3 | 21012222222221220201210022011 |
4 | 30201123122330313322213 |
5 | 24204312011434410241 |
6 | 313044310113015051 |
7 | 14412642501355042 |
oct | 1441333274677247 |
9 | 235888856653264 |
10 | 55073744060071 |
11 | 16603709830440 |
12 | 62157b1554487 |
13 | 249657c811039 |
14 | d85824d35c59 |
15 | 6578db50d281 |
hex | 3216daf37ea7 |
55073744060071 has 4 divisors (see below), whose sum is σ = 60080448065544. Its totient is φ = 50067040054600.
The previous prime is 55073744060039. The next prime is 55073744060077. The reversal of 55073744060071 is 17006044737055.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55073744060071 - 25 = 55073744060039 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 55073744059997 and 55073744060024.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55073744060077) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2503352002720 + ... + 2503352002741.
It is an arithmetic number, because the mean of its divisors is an integer number (15020112016386).
Almost surely, 255073744060071 is an apocalyptic number.
55073744060071 is a deficient number, since it is larger than the sum of its proper divisors (5006704005473).
55073744060071 is a wasteful number, since it uses less digits than its factorization.
55073744060071 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5006704005472.
The product of its (nonzero) digits is 2469600, while the sum is 49.
The spelling of 55073744060071 in words is "fifty-five trillion, seventy-three billion, seven hundred forty-four million, sixty thousand, seventy-one".
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