Base | Representation |
---|---|
bin | 110011010011011001… |
… | …011011111010010111 |
3 | 12021012001112100201012 |
4 | 303103121123322113 |
5 | 1400304041034210 |
6 | 41150053522435 |
7 | 3660042360410 |
oct | 632331337227 |
9 | 167161470635 |
10 | 55086268055 |
11 | 213a8842575 |
12 | a81434341b |
13 | 526b7449b0 |
14 | 294804a807 |
15 | 167618c305 |
hex | cd365be97 |
55086268055 has 16 divisors (see below), whose sum is σ = 81358181184. Its totient is φ = 34867791360.
The previous prime is 55086268009. The next prime is 55086268063.
55086268055 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 55086268055 - 28 = 55086267799 is a prime.
It is a super-3 number, since 3×550862680553 (a number of 33 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 55086267994 and 55086268012.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 60533906 + ... + 60534815.
It is an arithmetic number, because the mean of its divisors is an integer number (5084886324).
Almost surely, 255086268055 is an apocalyptic number.
55086268055 is a deficient number, since it is larger than the sum of its proper divisors (26271913129).
55086268055 is a wasteful number, since it uses less digits than its factorization.
55086268055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 121068746.
The product of its (nonzero) digits is 2880000, while the sum is 50.
The spelling of 55086268055 in words is "fifty-five billion, eighty-six million, two hundred sixty-eight thousand, fifty-five".
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