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551000101011 = 3183666700337
BaseRepresentation
bin10000000010010100010…
…10100101000010010011
31221200020010220021112120
420001022022211002103
533011422011213021
61101043112225323
754544203403443
oct10011212450223
91850203807476
10551000101011
111a2750213208
128a95499b243
133cc61161939
141c9506ca123
15e4ed1c92c6
hex804a2a5093

551000101011 has 4 divisors (see below), whose sum is σ = 734666801352. Its totient is φ = 367333400672.

The previous prime is 551000101009. The next prime is 551000101031. The reversal of 551000101011 is 110101000155.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 551000101011 - 21 = 551000101009 is a prime.

It is a super-2 number, since 2×5510001010112 (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (551000101031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91833350166 + ... + 91833350171.

It is an arithmetic number, because the mean of its divisors is an integer number (183666700338).

Almost surely, 2551000101011 is an apocalyptic number.

551000101011 is a deficient number, since it is larger than the sum of its proper divisors (183666700341).

551000101011 is a wasteful number, since it uses less digits than its factorization.

551000101011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 183666700340.

The product of its (nonzero) digits is 25, while the sum is 15.

Adding to 551000101011 its reverse (110101000155), we get a palindrome (661101101166).

The spelling of 551000101011 in words is "five hundred fifty-one billion, one hundred one thousand, eleven".

Divisors: 1 3 183666700337 551000101011