Base | Representation |
---|---|
bin | 1101001000110… |
… | …0001011100011 |
3 | 10211200101011121 |
4 | 3102030023203 |
5 | 103101201011 |
6 | 5244553111 |
7 | 1236225532 |
oct | 322141343 |
9 | 124611147 |
10 | 55100131 |
11 | 291145a9 |
12 | 16552797 |
13 | b552938 |
14 | 7464319 |
15 | 4c85e71 |
hex | 348c2e3 |
55100131 has 4 divisors (see below), whose sum is σ = 55764072. Its totient is φ = 54436192.
The previous prime is 55100081. The next prime is 55100153. The reversal of 55100131 is 13100155.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13100155 = 5 ⋅2620031.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55100131 is a prime.
It is a super-2 number, since 2×551001312 = 6072048872434322, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55100161) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 331846 + ... + 332011.
It is an arithmetic number, because the mean of its divisors is an integer number (13941018).
Almost surely, 255100131 is an apocalyptic number.
55100131 is a deficient number, since it is larger than the sum of its proper divisors (663941).
55100131 is an equidigital number, since it uses as much as digits as its factorization.
55100131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 663940.
The product of its (nonzero) digits is 75, while the sum is 16.
The square root of 55100131 is about 7422.9462479530. The cubic root of 55100131 is about 380.5258900641.
Adding to 55100131 its reverse (13100155), we get a palindrome (68200286).
It can be divided in two parts, 55100 and 131, that multiplied together give a triangular number (7218100 = T3799).
The spelling of 55100131 in words is "fifty-five million, one hundred thousand, one hundred thirty-one".
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