Base | Representation |
---|---|
bin | 11001000011101100011100… |
… | …01001100110100101100011 |
3 | 21020002202020101100101011221 |
4 | 30201312032021212211203 |
5 | 24210244430200304103 |
6 | 313105425352115511 |
7 | 14415011551511431 |
oct | 1441661611464543 |
9 | 236082211311157 |
10 | 55102520322403 |
11 | 16614936225224 |
12 | 621b2a2695b97 |
13 | 24991b74c01b8 |
14 | d86d94a31d51 |
15 | 6585229ad1bd |
hex | 321d8e266963 |
55102520322403 has 8 divisors (see below), whose sum is σ = 55430694683136. Its totient is φ = 54775263933000.
The previous prime is 55102520322383. The next prime is 55102520322491. The reversal of 55102520322403 is 30422302520155.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 55102520322403 - 25 = 55102520322371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55102500322403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 229372423 + ... + 229612528.
It is an arithmetic number, because the mean of its divisors is an integer number (6928836835392).
Almost surely, 255102520322403 is an apocalyptic number.
55102520322403 is a deficient number, since it is larger than the sum of its proper divisors (328174360733).
55102520322403 is a wasteful number, since it uses less digits than its factorization.
55102520322403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 458985665.
The product of its (nonzero) digits is 72000, while the sum is 34.
Adding to 55102520322403 its reverse (30422302520155), we get a palindrome (85524822842558).
The spelling of 55102520322403 in words is "fifty-five trillion, one hundred two billion, five hundred twenty million, three hundred twenty-two thousand, four hundred three".
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