Base | Representation |
---|---|
bin | 10000000010011001011… |
… | …10100111001010100111 |
3 | 1221200100010210220220202 |
4 | 20001030232213022213 |
5 | 33012014013220401 |
6 | 1101051250021115 |
7 | 54545235036041 |
oct | 10011456471247 |
9 | 1850303726822 |
10 | 551043101351 |
11 | 1a2772512a86 |
12 | 8a96727779b |
13 | 3cc6a039022 |
14 | 1c9562c0a91 |
15 | e501d7006b |
hex | 804cba72a7 |
551043101351 has 4 divisors (see below), whose sum is σ = 551046427704. Its totient is φ = 551039775000.
The previous prime is 551043101299. The next prime is 551043101393. The reversal of 551043101351 is 153101340155.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 153101340155 = 5 ⋅30620268031.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-551043101351 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (551043101051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1400900 + ... + 1750601.
It is an arithmetic number, because the mean of its divisors is an integer number (137761606926).
Almost surely, 2551043101351 is an apocalyptic number.
551043101351 is a deficient number, since it is larger than the sum of its proper divisors (3326353).
551043101351 is a wasteful number, since it uses less digits than its factorization.
551043101351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3326352.
The product of its (nonzero) digits is 4500, while the sum is 29.
The spelling of 551043101351 in words is "five hundred fifty-one billion, forty-three million, one hundred one thousand, three hundred fifty-one".
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