Base | Representation |
---|---|
bin | 10000000010011001100… |
… | …10000110000011111011 |
3 | 1221200100012112022021211 |
4 | 20001030302012003323 |
5 | 33012014231424311 |
6 | 1101051321343551 |
7 | 54545245560556 |
oct | 10011462060373 |
9 | 1850305468254 |
10 | 551044014331 |
11 | 1a2772a86a08 |
12 | 8a967637bb7 |
13 | 3cc6a298755 |
14 | 1c95647b69d |
15 | e501ea0821 |
hex | 804cc860fb |
551044014331 has 8 divisors (see below), whose sum is σ = 557393205600. Its totient is φ = 544698327360.
The previous prime is 551044014289. The next prime is 551044014347. The reversal of 551044014331 is 133410440155.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 551044014331 - 211 = 551044012283 is a prime.
It is a super-2 number, since 2×5510440143312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 551044014293 and 551044014302.
It is not an unprimeable number, because it can be changed into a prime (551044014931) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 559111 + ... + 1189408.
It is an arithmetic number, because the mean of its divisors is an integer number (69674150700).
Almost surely, 2551044014331 is an apocalyptic number.
551044014331 is a deficient number, since it is larger than the sum of its proper divisors (6349191269).
551044014331 is a wasteful number, since it uses less digits than its factorization.
551044014331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1752149.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 551044014331 its reverse (133410440155), we get a palindrome (684454454486).
The spelling of 551044014331 in words is "five hundred fifty-one billion, forty-four million, fourteen thousand, three hundred thirty-one".
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