Base | Representation |
---|---|
bin | 10000000010011100101… |
… | …01101101111110100011 |
3 | 1221200102000200010100220 |
4 | 20001032111231332203 |
5 | 33012042423130313 |
6 | 1101054053214123 |
7 | 54546013551024 |
oct | 10011625557643 |
9 | 1850360603326 |
10 | 551070130083 |
11 | 1a27867a4080 |
12 | 8a974331343 |
13 | 3cc72810765 |
14 | 1c959b18c4b |
15 | e50440d823 |
hex | 804e56dfa3 |
551070130083 has 32 divisors (see below), whose sum is σ = 843814920960. Its totient is φ = 316377210240.
The previous prime is 551070130069. The next prime is 551070130109. The reversal of 551070130083 is 380031070155.
551070130083 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 551070130083 - 24 = 551070130067 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is not an unprimeable number, because it can be changed into a prime (551070130183) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9258085 + ... + 9317417.
It is an arithmetic number, because the mean of its divisors is an integer number (26369216280).
Almost surely, 2551070130083 is an apocalyptic number.
551070130083 is a deficient number, since it is larger than the sum of its proper divisors (292744790877).
551070130083 is a wasteful number, since it uses less digits than its factorization.
551070130083 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 74179.
The product of its (nonzero) digits is 12600, while the sum is 33.
The spelling of 551070130083 in words is "five hundred fifty-one billion, seventy million, one hundred thirty thousand, eighty-three".
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