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55113032404034 = 21120857120110171
BaseRepresentation
bin11001000100000000000001…
…01110000000110001000010
321020010202100222200110020122
430202000000232000301002
524210432442243412114
6313114324430340242
714415533214646643
oct1442000056006102
9236122328613218
1055113032404034
111661933aaa87a0
12622133705a682
13249a1a1302947
14d876b0bb36ca
1565893a7bde8e
hex322000b80c42

55113032404034 has 16 divisors (see below), whose sum is σ = 90189286832736. Its totient is φ = 25050177055200.

The previous prime is 55113032404009. The next prime is 55113032404097. The reversal of 55113032404034 is 43040423031155.

It is a super-3 number, since 3×551130324040343 (a number of 42 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 55113032403985 and 55113032404003.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59596232 + ... + 60513939.

It is an arithmetic number, because the mean of its divisors is an integer number (5636830427046).

Almost surely, 255113032404034 is an apocalyptic number.

55113032404034 is a deficient number, since it is larger than the sum of its proper divisors (35076254428702).

55113032404034 is a wasteful number, since it uses less digits than its factorization.

55113032404034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 120131041.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 55113032404034 its reverse (43040423031155), we get a palindrome (98153455435189).

The spelling of 55113032404034 in words is "fifty-five trillion, one hundred thirteen billion, thirty-two million, four hundred four thousand, thirty-four".

Divisors: 1 2 11 22 20857 41714 229427 458854 120110171 240220342 1321211881 2642423762 2505137836547 5010275673094 27556516202017 55113032404034