Base | Representation |
---|---|
bin | 11001000100000000000001… |
… | …01110000000110001000010 |
3 | 21020010202100222200110020122 |
4 | 30202000000232000301002 |
5 | 24210432442243412114 |
6 | 313114324430340242 |
7 | 14415533214646643 |
oct | 1442000056006102 |
9 | 236122328613218 |
10 | 55113032404034 |
11 | 1661933aaa87a0 |
12 | 622133705a682 |
13 | 249a1a1302947 |
14 | d876b0bb36ca |
15 | 65893a7bde8e |
hex | 322000b80c42 |
55113032404034 has 16 divisors (see below), whose sum is σ = 90189286832736. Its totient is φ = 25050177055200.
The previous prime is 55113032404009. The next prime is 55113032404097. The reversal of 55113032404034 is 43040423031155.
It is a super-3 number, since 3×551130324040343 (a number of 42 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 55113032403985 and 55113032404003.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59596232 + ... + 60513939.
It is an arithmetic number, because the mean of its divisors is an integer number (5636830427046).
Almost surely, 255113032404034 is an apocalyptic number.
55113032404034 is a deficient number, since it is larger than the sum of its proper divisors (35076254428702).
55113032404034 is a wasteful number, since it uses less digits than its factorization.
55113032404034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 120131041.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 55113032404034 its reverse (43040423031155), we get a palindrome (98153455435189).
The spelling of 55113032404034 in words is "fifty-five trillion, one hundred thirteen billion, thirty-two million, four hundred four thousand, thirty-four".
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