Base | Representation |
---|---|
bin | 111110101010000000100100… |
… | …0110000101000100001010011 |
3 | 2200021101122112112211221100120 |
4 | 1331110001020300220201103 |
5 | 1034214214124034144110 |
6 | 5232054140404521323 |
7 | 224041634316131220 |
oct | 17524011060504123 |
9 | 2607348475757316 |
10 | 551131424131155 |
11 | 14a675584a5677a |
12 | 51990b669b0243 |
13 | 1a86a61630437a |
14 | 9a14c9076a947 |
15 | 43ab2d6b97870 |
hex | 1f54048c28853 |
551131424131155 has 32 divisors (see below), whose sum is σ = 1009941169595904. Its totient is φ = 251406295378176.
The previous prime is 551131424131117. The next prime is 551131424131157.
551131424131155 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 551131424131155 - 27 = 551131424131027 is a prime.
It is a super-3 number, since 3×5511314241311553 (a number of 45 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (551131424131157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5619726882 + ... + 5619824951.
It is an arithmetic number, because the mean of its divisors is an integer number (31560661549872).
Almost surely, 2551131424131155 is an apocalyptic number.
551131424131155 is a deficient number, since it is larger than the sum of its proper divisors (458809745464749).
551131424131155 is a wasteful number, since it uses less digits than its factorization.
551131424131155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11239552315.
The product of its digits is 180000, while the sum is 42.
The spelling of 551131424131155 in words is "five hundred fifty-one trillion, one hundred thirty-one billion, four hundred twenty-four million, one hundred thirty-one thousand, one hundred fifty-five".
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