Base | Representation |
---|---|
bin | 110011010101000111… |
… | …111000111111011001 |
3 | 12021021002000102102121 |
4 | 303111013320333121 |
5 | 1400333444114001 |
6 | 41153010301241 |
7 | 3660543444226 |
oct | 632507707731 |
9 | 167232012377 |
10 | 55115223001 |
11 | 21413119883 |
12 | a821b87821 |
13 | 52747420b7 |
14 | 294bc2694d |
15 | 16789ab6a1 |
hex | cd51f8fd9 |
55115223001 has 4 divisors (see below), whose sum is σ = 55122372772. Its totient is φ = 55108073232.
The previous prime is 55115222957. The next prime is 55115223049. The reversal of 55115223001 is 10032251155.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 13753425625 + 41361797376 = 117275^2 + 203376^2 .
It is a cyclic number.
It is not a de Polignac number, because 55115223001 - 29 = 55115222489 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55115223071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3563310 + ... + 3578743.
It is an arithmetic number, because the mean of its divisors is an integer number (13780593193).
Almost surely, 255115223001 is an apocalyptic number.
It is an amenable number.
55115223001 is a deficient number, since it is larger than the sum of its proper divisors (7149771).
55115223001 is an equidigital number, since it uses as much as digits as its factorization.
55115223001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7149770.
The product of its (nonzero) digits is 1500, while the sum is 25.
Adding to 55115223001 its reverse (10032251155), we get a palindrome (65147474156).
The spelling of 55115223001 in words is "fifty-five billion, one hundred fifteen million, two hundred twenty-three thousand, one".
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