Base | Representation |
---|---|
bin | 11001000100000111101101… |
… | …11111001111110101100001 |
3 | 21020011011000221020020101120 |
4 | 30202003312333033311201 |
5 | 24211014423003223340 |
6 | 313120250423322453 |
7 | 14416040464641231 |
oct | 1442036677176541 |
9 | 236134027206346 |
10 | 55117164117345 |
11 | 166200702740a0 |
12 | 62220aa8b0429 |
13 | 249a6ac2bc915 |
14 | d87983811cc1 |
15 | 658acd3b04d0 |
hex | 3220f6fcfd61 |
55117164117345 has 32 divisors (see below), whose sum is σ = 96224961982464. Its totient is φ = 26717790916800.
The previous prime is 55117164117341. The next prime is 55117164117403. The reversal of 55117164117345 is 54371146171155.
It is not a de Polignac number, because 55117164117345 - 22 = 55117164117341 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (55117164117341) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 34737871 + ... + 36289860.
It is an arithmetic number, because the mean of its divisors is an integer number (3007030061952).
Almost surely, 255117164117345 is an apocalyptic number.
55117164117345 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
55117164117345 is a deficient number, since it is larger than the sum of its proper divisors (41107797865119).
55117164117345 is a wasteful number, since it uses less digits than its factorization.
55117164117345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71032453.
The product of its digits is 1764000, while the sum is 51.
The spelling of 55117164117345 in words is "fifty-five trillion, one hundred seventeen billion, one hundred sixty-four million, one hundred seventeen thousand, three hundred forty-five".
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