Base | Representation |
---|---|
bin | 101000000110110000111… |
… | …1000001001111111011011 |
3 | 201111221122200200011012002 |
4 | 1100031201320021333123 |
5 | 1210302222244323312 |
6 | 15420114510311215 |
7 | 1106143415506121 |
oct | 120154170117733 |
9 | 21457580604162 |
10 | 5512085151707 |
11 | 1835731406342 |
12 | 7503421b850b |
13 | 30ca30bbba84 |
14 | 150b01a31911 |
15 | 985ae2e54c2 |
hex | 50361e09fdb |
5512085151707 has 4 divisors (see below), whose sum is σ = 5702157053520. Its totient is φ = 5322013249896.
The previous prime is 5512085151647. The next prime is 5512085151709. The reversal of 5512085151707 is 7071515802155.
5512085151707 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5512085151707 - 240 = 4412573523931 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5512085151709) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95035950863 + ... + 95035950920.
It is an arithmetic number, because the mean of its divisors is an integer number (1425539263380).
Almost surely, 25512085151707 is an apocalyptic number.
5512085151707 is a deficient number, since it is larger than the sum of its proper divisors (190071901813).
5512085151707 is a wasteful number, since it uses less digits than its factorization.
5512085151707 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 190071901812.
The product of its (nonzero) digits is 490000, while the sum is 47.
The spelling of 5512085151707 in words is "five trillion, five hundred twelve billion, eighty-five million, one hundred fifty-one thousand, seven hundred seven".
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