Base | Representation |
---|---|
bin | 111110101010100111000111… |
… | …1010111100010000011100010 |
3 | 2200021200120020020220220212122 |
4 | 1331111032033113202003202 |
5 | 1034222043202024041114 |
6 | 5232200151432024242 |
7 | 224050625024635343 |
oct | 17525161727420342 |
9 | 2607616206826778 |
10 | 551214213112034 |
11 | 14a6a76a91a442a |
12 | 519a5010832082 |
13 | 1a87537b1a8a14 |
14 | 9a18ca5a9c0ca |
15 | 43ad52ee25e8e |
hex | 1f5538f5e20e2 |
551214213112034 has 8 divisors (see below), whose sum is σ = 826821506125020. Its totient is φ = 275607044403696.
The previous prime is 551214213112019. The next prime is 551214213112051. The reversal of 551214213112034 is 430211312412155.
It can be written as a sum of positive squares in 2 ways, for example, as 547351993758025 + 3862219354009 = 23395555^2 + 1965253^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 551214213111985 and 551214213112003.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19061129 + ... + 38285180.
Almost surely, 2551214213112034 is an apocalyptic number.
551214213112034 is a deficient number, since it is larger than the sum of its proper divisors (275607293012986).
551214213112034 is a wasteful number, since it uses less digits than its factorization.
551214213112034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62152324.
The product of its (nonzero) digits is 28800, while the sum is 35.
Adding to 551214213112034 its reverse (430211312412155), we get a palindrome (981425525524189).
The spelling of 551214213112034 in words is "five hundred fifty-one trillion, two hundred fourteen billion, two hundred thirteen million, one hundred twelve thousand, thirty-four".
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