Base | Representation |
---|---|
bin | 10000000010110001000… |
… | …10000100111110001011 |
3 | 1221200211221110102211100 |
4 | 20001120202010332023 |
5 | 33012420213022110 |
6 | 1101123042432443 |
7 | 54553161253344 |
oct | 10013042047613 |
9 | 1850757412740 |
10 | 551241142155 |
11 | 1a2864287a70 |
12 | 8aa01662723 |
13 | 3cc9c088632 |
14 | 1c9747130cb |
15 | e51443dbc0 |
hex | 8058884f8b |
551241142155 has 48 divisors (see below), whose sum is σ = 1042903970784. Its totient is φ = 267125591040.
The previous prime is 551241142141. The next prime is 551241142157.
551241142155 is a `hidden beast` number, since 5 + 51 + 2 + 411 + 42 + 155 = 666.
551241142155 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 551241142155 - 218 = 551240880011 is a prime.
It is not an unprimeable number, because it can be changed into a prime (551241142157) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 632467 + ... + 1225763.
It is an arithmetic number, because the mean of its divisors is an integer number (21727166058).
Almost surely, 2551241142155 is an apocalyptic number.
551241142155 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
551241142155 is a deficient number, since it is larger than the sum of its proper divisors (491662828629).
551241142155 is a wasteful number, since it uses less digits than its factorization.
551241142155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 595196 (or 595193 counting only the distinct ones).
The product of its digits is 40000, while the sum is 36.
It can be divided in two parts, 551241 and 142155, that added together give a palindrome (693396).
The spelling of 551241142155 in words is "five hundred fifty-one billion, two hundred forty-one million, one hundred forty-two thousand, one hundred fifty-five".
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