Base | Representation |
---|---|
bin | 111110101011010000011111… |
… | …0001011100110010011000011 |
3 | 2200022000001112010102210012220 |
4 | 1331112200332023212103003 |
5 | 1034230022114101424103 |
6 | 5232305042255022123 |
7 | 224060221254301614 |
oct | 17526407613462303 |
9 | 2608001463383186 |
10 | 551303045342403 |
11 | 14a731343722952 |
12 | 519ba28250a943 |
13 | 1a8808670aca43 |
14 | 9a1d2d1859c0b |
15 | 43b09cd9d1c53 |
hex | 1f5683e2e64c3 |
551303045342403 has 32 divisors (see below), whose sum is σ = 738843343257600. Its totient is φ = 365651222351520.
The previous prime is 551303045342341. The next prime is 551303045342429. The reversal of 551303045342403 is 304243540303155.
It is not a de Polignac number, because 551303045342403 - 213 = 551303045334211 is a prime.
It is not an unprimeable number, because it can be changed into a prime (551303045342443) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 20648814148 + ... + 20648840846.
It is an arithmetic number, because the mean of its divisors is an integer number (23088854476800).
Almost surely, 2551303045342403 is an apocalyptic number.
551303045342403 is a deficient number, since it is larger than the sum of its proper divisors (187540297915197).
551303045342403 is a wasteful number, since it uses less digits than its factorization.
551303045342403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45679.
The product of its (nonzero) digits is 1296000, while the sum is 42.
Adding to 551303045342403 its reverse (304243540303155), we get a palindrome (855546585645558).
The spelling of 551303045342403 in words is "five hundred fifty-one trillion, three hundred three billion, forty-five million, three hundred forty-two thousand, four hundred three".
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