Base | Representation |
---|---|
bin | 11001000100100001111001… |
… | …10011100001100010000111 |
3 | 21020012111022112111220012011 |
4 | 30202100330303201202013 |
5 | 24211232214402213421 |
6 | 313130533305235051 |
7 | 14420046014646502 |
oct | 1442207463414207 |
9 | 236174275456164 |
10 | 55131220351111 |
11 | 16626023690613 |
12 | 6224972192a87 |
13 | 249bb0c45a3c8 |
14 | d88518566139 |
15 | 6591524004e1 |
hex | 32243cce1887 |
55131220351111 has 4 divisors (see below), whose sum is σ = 55131298103224. Its totient is φ = 55131142599000.
The previous prime is 55131220351037. The next prime is 55131220351153. The reversal of 55131220351111 is 11115302213155.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55131220351111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55131220351811) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37802580 + ... + 39233881.
It is an arithmetic number, because the mean of its divisors is an integer number (13782824525806).
Almost surely, 255131220351111 is an apocalyptic number.
55131220351111 is a deficient number, since it is larger than the sum of its proper divisors (77752113).
55131220351111 is an equidigital number, since it uses as much as digits as its factorization.
55131220351111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 77752112.
The product of its (nonzero) digits is 4500, while the sum is 31.
Adding to 55131220351111 its reverse (11115302213155), we get a palindrome (66246522564266).
The spelling of 55131220351111 in words is "fifty-five trillion, one hundred thirty-one billion, two hundred twenty million, three hundred fifty-one thousand, one hundred eleven".
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