Base | Representation |
---|---|
bin | 110011010110011001… |
… | …010000000010111101 |
3 | 12021022120011000002020 |
4 | 303112121100002331 |
5 | 1400404424113401 |
6 | 41155051350353 |
7 | 3661222644252 |
oct | 632631200275 |
9 | 167276130066 |
10 | 55136551101 |
11 | 21424166a05 |
12 | a8291523b9 |
13 | 5278c9bb88 |
14 | 29509b9429 |
15 | 167a7c0d36 |
hex | cd66500bd |
55136551101 has 4 divisors (see below), whose sum is σ = 73515401472. Its totient is φ = 36757700732.
The previous prime is 55136551097. The next prime is 55136551111. The reversal of 55136551101 is 10115563155.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 55136551101 - 22 = 55136551097 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55136551111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9189425181 + ... + 9189425186.
It is an arithmetic number, because the mean of its divisors is an integer number (18378850368).
Almost surely, 255136551101 is an apocalyptic number.
It is an amenable number.
55136551101 is a deficient number, since it is larger than the sum of its proper divisors (18378850371).
55136551101 is a wasteful number, since it uses less digits than its factorization.
55136551101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18378850370.
The product of its (nonzero) digits is 11250, while the sum is 33.
The spelling of 55136551101 in words is "fifty-five billion, one hundred thirty-six million, five hundred fifty-one thousand, one hundred one".
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