551411041333 has 4 divisors (see below), whose sum is σ = 551444341600. Its totient is φ = 551377741068.

The previous prime is 551411041309. The next prime is 551411041393. The reversal of 551411041333 is 333140114155.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 551411041333 - 2⁵ = 551411041301 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 551411041295 and 551411041304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (551411041303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16625283 + ... + 16658416.

It is an arithmetic number, because the mean of its divisors is an integer number (137861085400).

Almost surely, 2^551411041333 is an apocalyptic number.

It is an amenable number.

551411041333 is a deficient number, since it is larger than the sum of its proper divisors (33300267).

551411041333 is a wasteful number, since it uses less digits than its factorization.

551411041333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33300266.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 551411041333 its reverse (333140114155), we get a palindrome (884551155488).

The spelling of 551411041333 in words is "five hundred fifty-one billion, four hundred eleven million, forty-one thousand, three hundred thirty-three".