Base | Representation |
---|---|
bin | 11001000101000110000001… |
… | …00111011110101101010011 |
3 | 21020021100100221200020001021 |
4 | 30202203000213132231103 |
5 | 24212041423040434012 |
6 | 313143501412220311 |
7 | 14421333366216604 |
oct | 1442430047365523 |
9 | 236240327606037 |
10 | 55150611655507 |
11 | 16633274562615 |
12 | 622868430a697 |
13 | 24a08ac9b3514 |
14 | d89437a7ddab |
15 | 6598d99d2007 |
hex | 3228c09deb53 |
55150611655507 has 8 divisors (see below), whose sum is σ = 55158530942880. Its totient is φ = 55142692862400.
The previous prime is 55150611655499. The next prime is 55150611655523. The reversal of 55150611655507 is 70555611605155.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 55150611655507 - 23 = 55150611655499 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55150611655597) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 261508719 + ... + 261719527.
It is an arithmetic number, because the mean of its divisors is an integer number (6894816367860).
Almost surely, 255150611655507 is an apocalyptic number.
55150611655507 is a deficient number, since it is larger than the sum of its proper divisors (7919287373).
55150611655507 is a wasteful number, since it uses less digits than its factorization.
55150611655507 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 247133.
The product of its (nonzero) digits is 3937500, while the sum is 52.
The spelling of 55150611655507 in words is "fifty-five trillion, one hundred fifty billion, six hundred eleven million, six hundred fifty-five thousand, five hundred seven".
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