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55154363612651 = 487113253313373
BaseRepresentation
bin11001000101001101000000…
…10000000011110111101011
321020021201001102122101122222
430202212200100003313223
524212122114041101101
6313145322001504255
714421525355302302
oct1442464020036753
9236251042571588
1055154363612651
111663491a42a546
12622935094208b
1324a105a0c92c4
14d896b20a7439
15659a590ad01b
hex3229a0403deb

55154363612651 has 4 divisors (see below), whose sum is σ = 55267616926512. Its totient is φ = 55041110298792.

The previous prime is 55154363612641. The next prime is 55154363612707. The reversal of 55154363612651 is 15621636345155.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55154363612651 - 26 = 55154363612587 is a prime.

It is a super-3 number, since 3×551543636126513 (a number of 42 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 55154363612593 and 55154363612602.

It is not an unprimeable number, because it can be changed into a prime (55154363612641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56626656200 + ... + 56626657173.

It is an arithmetic number, because the mean of its divisors is an integer number (13816904231628).

Almost surely, 255154363612651 is an apocalyptic number.

55154363612651 is a deficient number, since it is larger than the sum of its proper divisors (113253313861).

55154363612651 is a wasteful number, since it uses less digits than its factorization.

55154363612651 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113253313860.

The product of its digits is 9720000, while the sum is 53.

The spelling of 55154363612651 in words is "fifty-five trillion, one hundred fifty-four billion, three hundred sixty-three million, six hundred twelve thousand, six hundred fifty-one".

Divisors: 1 487 113253313373 55154363612651