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5517232050147 = 315112179320199
BaseRepresentation
bin101000001001001010010…
…1010000000111111100011
3201112102221101110200112020
41100102110222000333203
51210343242401101042
615422325330232523
71106415103434666
oct120222452007743
921472841420466
105517232050147
111837932727314
12751339a25743
133103713018cc
1415106d4116dd
15987b10b73ec
hex50494a80fe3

5517232050147 has 8 divisors (see below), whose sum is σ = 7405026681600. Its totient is φ = 3653796059400.

The previous prime is 5517232050137. The next prime is 5517232050191. The reversal of 5517232050147 is 7410502327155.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5517232050147 - 27 = 5517232050019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5517232050099 and 5517232050108.

It is not an unprimeable number, because it can be changed into a prime (5517232050137) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6089659647 + ... + 6089660552.

It is an arithmetic number, because the mean of its divisors is an integer number (925628335200).

Almost surely, 25517232050147 is an apocalyptic number.

5517232050147 is a deficient number, since it is larger than the sum of its proper divisors (1887794631453).

5517232050147 is a wasteful number, since it uses less digits than its factorization.

5517232050147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12179320353.

The product of its (nonzero) digits is 294000, while the sum is 42.

The spelling of 5517232050147 in words is "five trillion, five hundred seventeen billion, two hundred thirty-two million, fifty thousand, one hundred forty-seven".

Divisors: 1 3 151 453 12179320199 36537960597 1839077350049 5517232050147