Base | Representation |
---|---|
bin | 111110110000010110100001… |
… | …0110110101110000010001011 |
3 | 2200101110222202100101120200102 |
4 | 1331200231002312232002023 |
5 | 1034323010030034040040 |
6 | 5234002434300400015 |
7 | 224161625653635602 |
oct | 17540550266560213 |
9 | 2611428670346612 |
10 | 552003203424395 |
11 | 14a981275703918 |
12 | 51ab1b03b4600b |
13 | 1a9018a9218408 |
14 | 9a45151b50a39 |
15 | 43c3d0b8b3515 |
hex | 1f60b42dae08b |
552003203424395 has 16 divisors (see below), whose sum is σ = 662571859651200. Its totient is φ = 441490555144704.
The previous prime is 552003203424373. The next prime is 552003203424401. The reversal of 552003203424395 is 593424302300255.
It is a cyclic number.
It is not a de Polignac number, because 552003203424395 - 238 = 551728325517451 is a prime.
It is a super-2 number, since 2×5520032034243952 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2488553582 + ... + 2488775388.
It is an arithmetic number, because the mean of its divisors is an integer number (41410741228200).
Almost surely, 2552003203424395 is an apocalyptic number.
552003203424395 is a deficient number, since it is larger than the sum of its proper divisors (110568656226805).
552003203424395 is a wasteful number, since it uses less digits than its factorization.
552003203424395 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 345814.
The product of its (nonzero) digits is 3888000, while the sum is 47.
The spelling of 552003203424395 in words is "five hundred fifty-two trillion, three billion, two hundred three million, four hundred twenty-four thousand, three hundred ninety-five".
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