Base | Representation |
---|---|
bin | 110011011010010000… |
… | …011010100000110101 |
3 | 12021111002001210121020 |
4 | 303122100122200311 |
5 | 1401023020443131 |
6 | 41205324211353 |
7 | 3662640451431 |
oct | 633220324065 |
9 | 167432053536 |
10 | 55201343541 |
11 | 214577a0483 |
12 | a846999b59 |
13 | 52895362b6 |
14 | 29594439c1 |
15 | 168131d996 |
hex | cda41a835 |
55201343541 has 4 divisors (see below), whose sum is σ = 73601791392. Its totient is φ = 36800895692.
The previous prime is 55201343507. The next prime is 55201343573. The reversal of 55201343541 is 14534310255.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 55201343541 - 210 = 55201342517 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55201343581) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9200223921 + ... + 9200223926.
It is an arithmetic number, because the mean of its divisors is an integer number (18400447848).
Almost surely, 255201343541 is an apocalyptic number.
It is an amenable number.
55201343541 is a deficient number, since it is larger than the sum of its proper divisors (18400447851).
55201343541 is a wasteful number, since it uses less digits than its factorization.
55201343541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18400447850.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 55201343541 its reverse (14534310255), we get a palindrome (69735653796).
The spelling of 55201343541 in words is "fifty-five billion, two hundred one million, three hundred forty-three thousand, five hundred forty-one".
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