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55213512054113 = 77887644579159
BaseRepresentation
bin11001000110111011001011…
…10001011101010101100001
321020111100201120212112201002
430203131211301131111201
524214104233041212423
6313232423130121345
714426021204615120
oct1443354561352541
9236440646775632
1055213512054113
1116657a12161016
1262388b9580255
1324a67c52c09aa
14d8c4c380dab7
1565b36bba2228
hex323765c5d561

55213512054113 has 4 divisors (see below), whose sum is σ = 63101156633280. Its totient is φ = 47325867474948.

The previous prime is 55213512054109. The next prime is 55213512054247. The reversal of 55213512054113 is 31145021531255.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55213512054113 - 22 = 55213512054109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55213512054013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3943822289573 + ... + 3943822289586.

It is an arithmetic number, because the mean of its divisors is an integer number (15775289158320).

Almost surely, 255213512054113 is an apocalyptic number.

It is an amenable number.

55213512054113 is a deficient number, since it is larger than the sum of its proper divisors (7887644579167).

55213512054113 is an equidigital number, since it uses as much as digits as its factorization.

55213512054113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7887644579166.

The product of its (nonzero) digits is 90000, while the sum is 38.

Adding to 55213512054113 its reverse (31145021531255), we get a palindrome (86358533585368).

The spelling of 55213512054113 in words is "fifty-five trillion, two hundred thirteen billion, five hundred twelve million, fifty-four thousand, one hundred thirteen".

Divisors: 1 7 7887644579159 55213512054113