Base | Representation |
---|---|
bin | 111110110010001011010011… |
… | …1101111110101000110001111 |
3 | 2200102100222010002100002021101 |
4 | 1331210112213233311012033 |
5 | 1034341112200040022203 |
6 | 5234313553120043531 |
7 | 224216015022345400 |
oct | 17544264757650617 |
9 | 2612328102302241 |
10 | 552254004220303 |
11 | 14aa68676171970 |
12 | 51b326387635a7 |
13 | 1a91c438178528 |
14 | 9a53344a579a7 |
15 | 43ca5d9b6041d |
hex | 1f645a7bf518f |
552254004220303 has 12 divisors (see below), whose sum is σ = 700819552666152. Its totient is φ = 430327795495920.
The previous prime is 552254004220297. The next prime is 552254004220333. The reversal of 552254004220303 is 303022400452255.
It is not a de Polignac number, because 552254004220303 - 29 = 552254004219791 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (552254004220333) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 512294994100 + ... + 512294995177.
It is an arithmetic number, because the mean of its divisors is an integer number (58401629388846).
Almost surely, 2552254004220303 is an apocalyptic number.
552254004220303 is a deficient number, since it is larger than the sum of its proper divisors (148565548445849).
552254004220303 is a wasteful number, since it uses less digits than its factorization.
552254004220303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1024589989302 (or 1024589989295 counting only the distinct ones).
The product of its (nonzero) digits is 288000, while the sum is 37.
Adding to 552254004220303 its reverse (303022400452255), we get a palindrome (855276404672558).
The spelling of 552254004220303 in words is "five hundred fifty-two trillion, two hundred fifty-four billion, four million, two hundred twenty thousand, three hundred three".
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