Base | Representation |
---|---|
bin | 11001000111101111010100… |
… | …01110011010100010011001 |
3 | 21020121000222101201211002100 |
4 | 30203313222032122202121 |
5 | 24220034100013303423 |
6 | 313253332511354013 |
7 | 14431031652566505 |
oct | 1443675216324231 |
9 | 236530871654070 |
10 | 55241504041113 |
11 | 16668876985175 |
12 | 624220bb22909 |
13 | 24a9336664400 |
14 | d8d9bb2b5305 |
15 | 65be59384343 |
hex | 323dea39a899 |
55241504041113 has 72 divisors (see below), whose sum is σ = 88429022826144. Its totient is φ = 33198087686400.
The previous prime is 55241504041103. The next prime is 55241504041127. The reversal of 55241504041113 is 31114040514255.
55241504041113 is a `hidden beast` number, since 5 + 5 + 241 + 5 + 0 + 404 + 1 + 1 + 1 + 3 = 666.
It is not a de Polignac number, because 55241504041113 - 28 = 55241504040857 is a prime.
It is not an unprimeable number, because it can be changed into a prime (55241504041103) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 368863458 + ... + 369013188.
Almost surely, 255241504041113 is an apocalyptic number.
It is an amenable number.
55241504041113 is a deficient number, since it is larger than the sum of its proper divisors (33187518785031).
55241504041113 is a wasteful number, since it uses less digits than its factorization.
55241504041113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 155447 (or 155431 counting only the distinct ones).
The product of its (nonzero) digits is 48000, while the sum is 36.
Adding to 55241504041113 its reverse (31114040514255), we get a palindrome (86355544555368).
The spelling of 55241504041113 in words is "fifty-five trillion, two hundred forty-one billion, five hundred four million, forty-one thousand, one hundred thirteen".
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