Base | Representation |
---|---|
bin | 101000001100110001110… |
… | …1111000001100100001010 |
3 | 201120011222211112010001200 |
4 | 1100121203233001210022 |
5 | 1211010200302323333 |
6 | 15430052302325030 |
7 | 1110111452311053 |
oct | 120314357014412 |
9 | 21504884463050 |
10 | 5525001214218 |
11 | 184015a170272 |
12 | 752947889776 |
13 | 31100ba82105 |
14 | 1515a918b72a |
15 | 98ab81b6c13 |
hex | 50663bc190a |
5525001214218 has 12 divisors (see below), whose sum is σ = 11970835964178. Its totient is φ = 1841667071400.
The previous prime is 5525001214211. The next prime is 5525001214283. The reversal of 5525001214218 is 8124121005255.
5525001214218 is a `hidden beast` number, since 5 + 5 + 2 + 500 + 1 + 2 + 142 + 1 + 8 = 666.
It can be written as a sum of positive squares in only one way, i.e., 5521762124649 + 3239089569 = 2349843^2 + 56913^2 .
It is a super-3 number, since 3×55250012142183 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (5525001214211) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 153472255933 + ... + 153472255968.
Almost surely, 25525001214218 is an apocalyptic number.
5525001214218 is an abundant number, since it is smaller than the sum of its proper divisors (6445834749960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5525001214218 is a wasteful number, since it uses less digits than its factorization.
5525001214218 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 306944511909 (or 306944511906 counting only the distinct ones).
The product of its (nonzero) digits is 32000, while the sum is 36.
The spelling of 5525001214218 in words is "five trillion, five hundred twenty-five billion, one million, two hundred fourteen thousand, two hundred eighteen".
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