Base | Representation |
---|---|
bin | 11001001000000011011011… |
… | …10101011100101010000101 |
3 | 21020122001211221001010222120 |
4 | 30210001231311130222011 |
5 | 24220223203304221201 |
6 | 313302320201520153 |
7 | 14431563360122235 |
oct | 1444015565345205 |
9 | 236561757033876 |
10 | 55252302023301 |
11 | 16672408081a99 |
12 | 62443241a3059 |
13 | 24aa367779196 |
14 | d903233d9cc5 |
15 | 65c38c31b536 |
hex | 32406dd5ca85 |
55252302023301 has 4 divisors (see below), whose sum is σ = 73669736031072. Its totient is φ = 36834868015532.
The previous prime is 55252302023263. The next prime is 55252302023357. The reversal of 55252302023301 is 10332020325255.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 55252302023301 - 222 = 55252297828997 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55252302023801) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9208717003881 + ... + 9208717003886.
It is an arithmetic number, because the mean of its divisors is an integer number (18417434007768).
Almost surely, 255252302023301 is an apocalyptic number.
It is an amenable number.
55252302023301 is a deficient number, since it is larger than the sum of its proper divisors (18417434007771).
55252302023301 is a wasteful number, since it uses less digits than its factorization.
55252302023301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18417434007770.
The product of its (nonzero) digits is 54000, while the sum is 33.
Adding to 55252302023301 its reverse (10332020325255), we get a palindrome (65584322348556).
The spelling of 55252302023301 in words is "fifty-five trillion, two hundred fifty-two billion, three hundred two million, twenty-three thousand, three hundred one".
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