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55252800303 = 318417600101
BaseRepresentation
bin110011011101010100…
…101101001100101111
312021121122220002000020
4303131110231030233
51401124204102203
641214403133223
73664134024231
oct633524551457
9167548802006
1055252800303
1121483846728
12a860074213
1352970b179c
1429621da251
151685ad5153
hexcdd52d32f

55252800303 has 4 divisors (see below), whose sum is σ = 73670400408. Its totient is φ = 36835200200.

The previous prime is 55252800301. The next prime is 55252800311. The reversal of 55252800303 is 30300825255.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55252800303 - 21 = 55252800301 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55252800301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9208800048 + ... + 9208800053.

It is an arithmetic number, because the mean of its divisors is an integer number (18417600102).

Almost surely, 255252800303 is an apocalyptic number.

55252800303 is a deficient number, since it is larger than the sum of its proper divisors (18417600105).

55252800303 is a wasteful number, since it uses less digits than its factorization.

55252800303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18417600104.

The product of its (nonzero) digits is 36000, while the sum is 33.

The spelling of 55252800303 in words is "fifty-five billion, two hundred fifty-two million, eight hundred thousand, three hundred three".

Divisors: 1 3 18417600101 55252800303